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4 years ago

13

13. What is a simpler form of each product?

1 answer:

saul85 [17]4 years ago

7 0

13. (a-b)^2=a^2-2ab+b^2
B is the answer
14. B is the answer
( x+9)(x-3)= x^2+6x-27
15. B is the answer
(x+6)(x-5)=x^2+x-30
16. D is the answer
(x-6y)(x-4y)=x^2-10xy+24y^2
17. C is the answer
(2x+5)(3x-4)=6x^2+7x-20
18. B is the answer
(5x+7)(x-2)=5x^2-3x-14

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Write the equation of each line in slope-intercept form <br> (just do the graph questions)

anyanavicka [17]

Step-by-step explanation:

x=2 y=0

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y=mx+b

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.......

x=0 y=4

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3 years ago

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nirvana33 [79]

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aleksandr82 [10.1K]

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Rom4ik [11]

Answer:

D. $\frac{4x^{2} \sqrt{29}}{29}$

Step-by-step explanation:

Given the expression:

$\frac{40x^{2} \sqrt{x^{12} } }{10x^{2} \sqrt{29x^{8} } }$

divide by the common factor to have;

$\frac{4\sqrt{x^{12} } }{\sqrt{29x^{8} } }$ = $\frac{4(x^{12}) ^{\frac{1}{2} } }{(29x^{8}) ^{\frac{1}{2} } }$

= $\frac{4x^{6} }{\sqrt{29}x^{4} }$

= $\frac{4x^{2} }{\sqrt{29} }$

Rationalize the denominator, we have;

$\frac{4x^{2} }{\sqrt{29} }$ x $\frac{\sqrt{29} }{\sqrt{29} }$

So that,

$\frac{4x^{2} \sqrt{29} }{29}$

Thus,

$\frac{40x^{2} \sqrt{x^{12} } }{10x^{2} \sqrt{29x^{8} } }$ = $\frac{4x^{2} \sqrt{29} }{29}$

The correct option is D.

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3 years ago

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lapo4ka [179]

54

Step-by-step explanation:

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37

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2 years ago