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lakkis [162]
3 years ago
6

A six-sided number cube is labeled with the numbers 1-6, one number on each face. Each number is used exactly once.

Mathematics
2 answers:
olchik [2.2K]3 years ago
4 0

Answer:

it would be 30 because you can only use 1 side once so it would be 6 times 5

AlladinOne [14]3 years ago
3 0

Answer: 15

Step-by-step explanation: 1+2+3+4+5=15

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The price of a watch was increased by 10% to £132. What was the price before the increase?
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Find the present value of $ 3,000 at a simple interest rate of 6 % in 9 years ?
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Is it anual intrest rate? if so then it would be 1620$ inrest rate  and if it was 6% in 9 years it would be 180$ interest rate

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A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
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Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

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3 years ago
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