Answer:
50% wild type and 50% black i.e. 1:1 phenotypic ratio
Explanation:
Given, b+ = wild type allele
b = recessive allele
b+b+ = dominant wild type
b+b = heterozygous wild type
bb = recessive black
First cross: female b+b (wild type) X male bb (black) = bb, bb, b+b, b+b
Since bb and b+b are in 1:1 phenotypic ratio, 52 black and 58 wild type progeny are produced.
From this progeny second cross occurs between:
female bb (black) X male (wild type) b+b = bb, bb, b+b, b+b
Again the same 1:1 phenotypic ratio is obtained. Half of the progeny will be be black (bb), other half will be wild type (b+b).
Adhesion allows for it to be easily attracted to glass
Fibrous root are a pattern of root growth where all branches are about the same size. A fibrous system is usually formed by thin, moderately branching roots growing from the stem. It is universal in monocotyledonous plants and ferns. Examples of plants that have fibrous root system include; grass, wheat, maize, banana, white clover among others.
