Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
Your answer is Y=-4 5
———
- -6, 6
A hole occurs when both numerator and denominator of a rational function have the same factor.
<u>Step-by-step explanation:</u>
While graphing rational function, it has to be converted into the lowest terms by factoring the numerator and denominator. If the numerator and denominator has the same factor, a hole is said to have occurred and to solve the rational function, you have to set the common factor to zero.
After you set it to zero and solve, you obtain the x value which can be then used to find out the value of y.
Step-by-step explanation:
The length of a rectangle, l = 3 units
The breadth of a rectangle, b = 4 units
Nancy needs to increase both the length and the width of the rectangle by 2 units.
The area of a rectangle is given by
A = length(l) × breadth(b)
Here,
A = 3 × 4
= 12 unit²
If both length and width of the rectangle increase by 2 units,
New length = (4+2) = 6 units
New width = (3+2) = 5 units
New area = 6 × 5 = 30 unit²
Hence, new area becomes 30 unit².
C
first set up an equation
$52+8n ≥ 144
bacause she can spend 144 or less
solve 144-52=92
92/8=11.5
