Let's assume
people were in the original group of winners as x
A group of winning ticket holders share equally 90,000,000 lottery
Before the money is divided, three more winning ticket holders are declared
so, total number of winning tickes =x+3
each persons share is reduced to 5,000,000
so, total money =5,000,000*(x+3)
and this must be equal to total money

now, we can solve for x
and we get

Subtrac both sides by 3


so,
number of people were in the original group of winners is 15 ...........Answer
Answer:
418
Step-by-step explanation:
fig 2 = fig 1 + 5
fig 3 = fig 2 + 7 or fig 1 +5+7 16
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
4+5+7+9+11+13+15+17+18+19+21+23+25+27+29+31+33+35+37+39
<span>-1 + n=8(n+6)
Use distributive property
-1 + n= 8n + 48
Subtract n from both sides
-1= 7n + 48
Subtract 48 from both sides
-49= 7n
Divide 7 on both sides so that the only thing remaining on the right sides is the varible n.
Final Answer: -7 = n</span>
Vertical angles are congruent, so:
