$x^2+6x-10=30 \ \ /-30\\\\x^2+6x-40=0\\\\a=1, \ b=6, \ c=-40\\\\\Delta=b^2-4ac=6^2-4\cdot1\cdot(-40)=36+160=196\\\\\sqrt{\Delta}=\sqrt{196}=14\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-14}{2}=\boxed{-10}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+14}{2}=\boxed4$

8 0

3 years ago

The smaller triangle is the image of the larger triangle after a dilation. The center of the dilation is (4,2). What is the scal

zzz [600]

Small triangle: The side // x axis has a length of 4
Large triangle: The side // x axis has a length of 12

So Small/Large = 4/12 = 1/3

Small triangle: The side // y axis has a length of 3
Large triangle: The side // y axis has a length of 9

So Small/Large = 3/9 = 1/3

So the scale factor to obtain this dilatation is 1/3

7 0

3 years ago

Read 2 more answers

Simplify the following polynomial expression. (5x^4-9x^3+7x-1)+(-8x^4+4x^2-3x+2)-(-4x^3+5x-1)(2x-7)

Anton [14]

Answer:

5x^4 - 37x^3 - 6x^2 + 41x - 6

Step-by-step explanation:

5 0

3 years ago