It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.
Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is
<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)
The cosine of the angle between the vectors can be obtained from the dot product identity,
<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>) ==> cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)
so that
<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)
For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is
<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))
==> <em>W</em> ≈ 5.12 J
(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).
Answer:
Dados dos ángulos vecinos, ambos son complementarios si la suma de sus medidas es igual a 90° y suplementarios si esa suma de medidas es igual a 180°. Puesto que uno de los ángulos es el ángulo agudo mencionado en el enunciado, es decir, un ángulo cuya medida es mayor que 0° y menor que 90°. Entonces, el ángulo complementario debe ser inevitablemente menor que el ángulo suplementario.
Step-by-step explanation:
Dados dos ángulos vecinos, ambos son complementarios si la suma de sus medidas es igual a 90° y suplementarios si esa suma de medidas es igual a 180°. Puesto que uno de los ángulos es el ángulo agudo mencionado en el enunciado, es decir, un ángulo cuya medida es mayor que 0° y menor que 90°. Entonces, el ángulo complementario debe ser inevitablemente menor que el ángulo suplementario.
Your answer to your question should be B if not then i dont know
so if 5.5 is in meter let change it to cm because the question want us to give the answer in cm.
now we multiply 5.5 times 100 which is equal to 550.
next we subtract 550 - 220= 330.
finally, the difference between a teacher and student is 330cm .meaning the teacher's desk is 330 cm longer or taller than the student.