2 years ago

I need help please.

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

5 0

Answer:

17/42

Step-by-step explanation:

you have to add all the jobs/assistan/worlerst and then make it as your denominator and then add how many profferser and instructor there are and make that your numerator

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3 years ago

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3 years ago

How did u get this and what is it I need help so bad

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Step-by-step explanation:

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2 years ago

Condense the following logs into a single log:

mamaluj [8]

QUESTION 1

The given logarithm is

$8\log_g(x)+5\log_g(y)$

We apply the power rule of logarithms; $n\log_a(m)=\log_(m^n)$

$=\log_g(x^8)+\log_g(y^5)$

We now apply the product rule of logarithm;

$\log_a(m)+\log_a(n)=\log_a(mn)$

$=\log_g(x^8y^5)$

QUESTION 2

The given logarithm is

$8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)$

We apply the power rule of logarithm to get;

$=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)$

We apply the product to obtain;

$=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)$

We apply the quotient rule; $\log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )$

$=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})$

$=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})$

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3 years ago

Can someone please do this ill mark brainliest

Svet_ta [14]

Answer:

-60 im pretty sure this is it

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3 years ago