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3 years ago

Please help due today!

Mathematics

1 answer:

Ann [662]3 years ago

4 0

M/_XYZ is 50°, if you need to copy and paste the degrees symbol, here it is: °

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I am posting my work for an application of integrals problem. I would love to know if anyone else agrees with my work!

quester [9]

Your work appears to be correct.

The results from a graphing calculator are in agreement.

8 0

3 years ago

9. If f(x)=-2x^2+4x-6, then f(2)=

Romashka-Z-Leto [24]

Answer:

f(2) = -6

General Formulas and Concepts:

Order of Operations: BPEMDAS

Substitution and Evaluation

Step-by-step explanation:

Step 1: Define

f(x) = -2x² + 4x - 6

f(2) is x = 2

Step 2: Solve

Substitute: f(2) = -2(2)² + 4(2) - 6
Exponents: f(2) = -2(4) + 4(2) - 6
Multiply: f(2) = -8 + 8 - 6
Add: f(2) = -6

3 0

3 years ago

I’ll give brainliest

motikmotik

Answer:

v= 5/6

Step-by-step explanation:

You have to divide -6 on both sides to isolate the variable V. Then it would become -5/-6. The negative signs cancel out.

6 0

2 years ago

Read 2 more answers

Please help quick for 25 points with explanations. Any silly and absurd answers will be reported.

amid [387]

Answer:

Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11± $\sqrt{61}$ )/2. So, PQ= $\frac{\sqrt{61} }{2}$ , PQ²= $\frac{61}{4}$ . Thus, the answer is 61+4=65.

Step-by-step explanation:

4 0

2 years ago

Can you help me?! I would really appreciate it

sweet [91]

Answer:

(3 , 8)

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers