Wath is six hundred ninety- two thousand,four

What proportion of a normal distribution corresponds to z scores greater than 1.04?

Tom [10]

We would need to look over the z table to find the area under the standard normal distribution curve to the left of z = 1.04. Then we'll subtract it from 1 to get the proportion of a normal distribution corresponding to z scores greater than 1.04.
By looking at the z table, we can see that the area to the left of z = 1.04 is 0.8508. So the proportion of a normal distribution to the right of z = 1.04 is 1 – 0.8508 = 0.1492.

The answer is 0.1492.

7 0

3 years ago

Read 2 more answers

A standardized exam's scores are normally distributed. In a recent year, the mean test score was 14901490 and the standard dev

kicyunya [14]

<h2>Answer with explanation:</h2>

Given : A standardized exam's scores are normally distributed.

Mean test score : $\mu=1490$

Standard deviation : $\sigma=320$

Let x be the random variable that represents the scores of students .

z-score : $z=\dfrac{x-\mu}{\sigma}$

We know that generally , z-scores lower than -1.96 or higher than 1.96 are considered unusual .

For x= 1900

$z=\dfrac{1900-1490}{320}\approx1.28$

Since it lies between -1.96 and 1.96 , thus it is not unusual.

For x= 1240

$z=\dfrac{1240-1490}{320}\approx-0.78$

Since it lies between -1.96 and 1.96 , thus it is not unusual.

For x= 2190

$z=\dfrac{2190-1490}{320}\approx2.19$

Since it is greater than 1.96 , thus it is unusual.

For x= 1240

$z=\dfrac{1370-1490}{320}\approx-0.38$

Since it lies between -1.96 and 1.96 , thus it is not unusual.

5 0

3 years ago

What is the slope intercept form of 6x-2y-4=0

saveliy_v [14]

Answer:

Step-by-step explanation:

y = 3x - 2

8 0

3 years ago

If you own 2.08% of stock out of 48 million outstanding stock pool then what percentage will you own for 16 million outstanding

AveGali [126]

Answer:

6.24%

Step-by-step explanation:

The first step is to determine how much stock is owned when there are 48 million outstanding stock

$\frac{2.08}{100}$ x 48 million = 0.9984 million

So, i own 0.9984 million shares.

If there are 16 million outstanding stock

(0.9984 / 16 million ) x 100 = 6.24%

8 0

3 years ago

(4x-9)(2x^2+2x+1) (4x−9)(2x 2 +2x+1)

tia_tia [17]

Answer:

$(4x-9)^2*(2x^2+2x+1)^2$

Step-by-step explanation:

(((4x-9)•(((2•(x2))+2x)+1))•(4x-9))•((2x2+2x)+1)

] (((4x-9)•((2x2+2x)+1))•(4x-9))•(2x2+2x+1)

Trying to factor by splitting the middle term

Factoring 2x2+2x+1

The first term is, 2x2 its coefficient is 2 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 2 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3

2 + 1 = 3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

((4x-9)•(2x2+2x+1)•(4x-9))•(2x2+2x+1)

Multiplying Exponential Expressions:

4.1 Multiply (4x-9) by (4x-9)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (4x-9) and the exponents are :

1 , as (4x-9) is the same number as (4x-9)1

and 1 , as (4x-9) is the same number as (4x-9)1

The product is therefore, (4x-9)(1+1) = (4x-9)2

Trying to factor by splitting the middle term

5.1 Factoring 2x2+2x+1

The first term is, 2x2 its coefficient is 2 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 2 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3

2 + 1 = 3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Multiplying Exponential Expressions:

5.2 Multiply (2x2+2x+1) by (2x2+2x+1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (2x2+2x+1) and the exponents are :

1 , as (2x2+2x+1) is the same number as (2x2+2x+1)1

and 1 , as (2x2+2x+1) is the same number as (2x2+2x+1)1

The product is therefore, (2x2+2x+1)(1+1) = (2x2+2x+1)2

Final result :

(4x - 9)2 • (2x2 + 2x + 1)2

6 0

2 years ago