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PIT_PIT [208]
3 years ago
10

Rosters Chicken advertises​ "lite" chicken with​ 30% fewer calories than standard chicken. When the process for​ "lite" chicken

breast production is in​ control, the average chicken breast contains 430 ​calories, and the standard deviation in caloric content of the chicken breast population is 30 calories. Rosters wants to design an x overbar​-chart to monitor the caloric content of chicken​ breasts, where 25 chicken breasts would be chosen at random to form each sample. ​a) What are the lower and upper control limits for this chart if these limits are chosen to be four standard deviations from the​ target?
Mathematics
1 answer:
Agata [3.3K]3 years ago
4 0

Answer:

Lower control limit: 310

Upper control limit: 550

Step-by-step explanation:

The problem states that the average chicken breast contains 430 ​calories, and the standard deviation in caloric content of the chicken breast population is 30 calories.

a) What are the lower and upper control limits for this chart if these limits are chosen to be four standard deviations from the​ target?

The lower control limit is the mean subtracted by four standard deviations. So 430 - 4*30 = 310;

The upper control limit is the mean added four standard deviations. So 430 + 4*30 = 550;

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Ne4ueva [31]

Answer:

2/7

Step-by-step explanation:

There are 22 (12 + 10) total students in the class. That means that the chance of the first student picked being a girl is 12/22.

Now, we must calculate the chance of the next student to be picked <em>also </em>being a girl - however, there is a trap here! Remember that since a girl has been picked, the total student pool has decreased to 21 and and the total number of girls has decreased to 11. This means the new chance of girl being picked is 11/21.

To find the probability of both these events happening in conjunction, these fractions must be multiplied. 12/22 * 11/21 = 132/462, which simplifies to 2/7.

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3 years ago
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Please answer ASAP ❤️Will earn 15 points (hope your answers are valid )
svetoff [14.1K]

Answer:  The cost of one rose bush is $7 and the cost of one shrub is also $7

Step-by-step explanation:

The situtation can be represented by the systems of the equations.

10x + 4y  =  98   x in this case is the cost of  one rose bushes

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Solve the system of equation using the elimination method.

10x +4y = 98

9x + 9y = 126     eliminate the y variable so you will have to multiply 9 on top                                          and -4 down.

9(10x +4) = (98)(9)

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You will now have the new two systems of equations

90x +36y = 882

-36x +-36y = -504    Now add the equations

0  + 54x = 378      

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Now we know that the cost of one rose bush is 7 so we will plot it into one of the equations and solve for the cost of one shrub.

90(7) +36y=882

630 +36y = 882

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Check:  10(7) + 4(7)= 98

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so one rose bush is actually 7 dollars the same as 1 shrub.

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Step-by-step explanation:

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70 + 1 = 71

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