How to Learn Math Fast?
Step-by-step explanation:
<u>∆</u><u> </u><u>Engage With the Subject. ...</u>
<u>∆</u><u> </u><u>Start From the Basics. ...</u>
<u>∆</u><u> </u><u>Develop Number Sense Rather Than</u> <u>∆</u><u> </u><u>Memorizing</u>. ...
<u>∆</u><u> </u><u>Have a Goal in Mind. ...</u>
<u>∆</u><u> </u><u>Answering Practice Questions Is </u><u>Crucial. ...</u>
<u>∆</u><u> </u><u>Keep Track of Math Vocabulary. ...</u>
<u>∆</u><u> </u><u>Tricks and Tips to Learn Math Easily. ...</u>
<u>∆</u><u> </u><u>Master Problem </u><u>Solving.</u>
<h3><u>Hope </u><u>this </u><u>can </u><u>help</u><u> </u><u>you</u><u>:</u><u>)</u></h3>
Answer:
100% increase from 100 is 200, the difference is 100.
100% decrease from 100 is 0, the difference is -100
error means that you were quite a long way off from the true value.
2(n - 1) + 4n = 2(3n - 1)
2n - 2 + 4n = 6n -2
6n - 2 = 6n - 2 (equal)
6n - 6n = 2 - 2
0 = 0
whatever value you put into the place of n, you'll get 0 = 0
Assuming width=diameter
diameter/2=radius
area=hpir^2
w=d=2
d/2=2/2=1=r
h=6
area=6pi1^2
area=6pi1
area=6pi
aprox pi=3.141592
area=18.85 cm³
Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.
The length of the poster in its frame is ...
(frame width on one side) + (poster length) + (frame width on the other side)
2 in + 32 in + 2 in = 36 in
Likewise, the width of the poster in its frame is ...
2 in + 24 in + 2 in = 28 in
The area of a rectangle 36 in by 28 in is the product of these dimensions:
Area = (36 in)×(28 in) = (36×28) in² = 1008 in²