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77julia77 [94]
3 years ago
5

Solve 6x^5+x^4-4x^3-4x^2+x+6=0

Mathematics
1 answer:
Firlakuza [10]3 years ago
3 0

±1±12±13±162±23±3±32±6±1±12±13±16±2,±23±3±32±6
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I need some help with this!!! Plz
melamori03 [73]
I would say to divide 121.10 by 3
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3 years ago
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What is the answer 4x + 17 + 5x -10 in the simplest form
antoniya [11.8K]

Answer:

9x+7

Step-by-step explanation:

Let's simplify step-by-step.

4x+17+5x−10

=4x+17+5x+−10

Combine Like Terms:

=4x+17+5x+−10

=(4x+5x)+(17+−10)

=9x+7

8 0
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Help someoneee!!!! <br> ill give a brainliest
Serjik [45]

Answer:

-13.5

Step-by-step explanation:

-4/3w=18

You would need to get the w by itself on one side so the easiest way to do so would be to divide both sides my -4/3.

This would give you an answer of w= -27/2 or w= -13.5

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3 years ago
If 10^x = 5, then what is x?
REY [17]

Answer:

what is ∧

Step-by-step explanation:

8 0
3 years ago
consider the followin polynomials equations a=3x2(x-1) b= -3x3+4x2-2x+1 . perform each operation and determine if the result is
Sedaia [141]

Answer:

All three operations lead to polynomials.

See explanations below.

Step-by-step explanation:

Polynomial a = 3x^2(x-1)=3x^3-3x^2

Polynomial b = -3x^3+4x^2-2x+1

Therefore:

a + b = 3x^3-3x^2+(-3x^3+4x^2-2x+1)=\\=3x^3-3x^2-3x^3+4x^2-2x+1=\\=x^2-2x+1

where we have combined all like terms. This is clearly another polynomial (of grade 2)

a - b (here we need to flip all signs inside the parenthesis when we remove this grouping symbol):3x^3-3x^2-(-3x^3+4x^2-2x+1)=\\3x^3-3x^2+3x^3-4x^2+2x-1=\\6x^3-7x^2+2x-1

which is clearly another polynomial (but of grade 3)

a * b : (here we use distributive property to multiply each term of the first polynomial by each term of the second one, and then combine like terms)

(3x^3-3x^2)*(-3x^3+4x^2-2x+1)=\\-9x^6+12x^5-6x^4+3x^3+9x^5-12x^4+6x^3-3x^2=\\-9x^6+21x^5-18x^4+9x^3-3x^2 which is indeed another polynomial (this time of grade 6)

5 0
4 years ago
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