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krek1111 [17]
3 years ago
13

TEP 1

Mathematics
1 answer:
777dan777 [17]3 years ago
3 0

Answer:

A perpendicular line drawn from a point not on a line to a line

• A perpendicular line drawn through a given point on a given line

• A quadrilateral with at least one pair of parallel lines

• A segment bisected by a perpendicular line, ray, or segment

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The snack bar at your school has added sushi to its menu. The ingredients for one roll include sushi​ rice, seaweed​ sheets, cuc
amid [387]

Answer:

The answer si:  

- 16 servings - 6 oz of salmon

- 24 servings - 9 oz of salmon

- 80 servings - 30 oz of salmon

- 100 servings - 37.5 oz of salmon

1 roll is 8 servings and it is also made of 3oz of smoked salmon. That means that 3oz of smoked salmon is needed fo 8 servings.

Now, let's made some proportions:

16 servings:

3 oz is for 8 servings, how much oz is for 16 servings:

3 : 8 = x : 16

x = 3 · 16 ÷ 8 = 6 oz

24 servings:

3 oz is for 8 servings, how much oz is for 24 servings:

3 : 8 = x : 24

x = 3 · 24 ÷ 8 = 9 oz

80 servings:

3 oz is for 8 servings, how much oz is for 80 servings:

3 : 8 = x : 80

x = 3 · 80 ÷ 8 = 30 oz

100 servings:

3 oz is for 8 servings, how much oz is for 100 servings:

3 : 8 = x : 100

x = 3 · 100 ÷ 8 = 37.5 oz

5 0
3 years ago
Determine if the triangle is similar. If similar, state how and complete the similarity statement.
Yuri [45]

Answer:

It would be...

Step-by-step explanation:

Similar By: 22.5 and 27

ABCD: G AND H AND F

I am not sure but I try hard

8 0
3 years ago
Select the equation has no solution. A) 2x + 17 - 7x - 6 = 8 - 10x - 19 + 5x B) 7 + 16x + 1 - 4x = 24 + 8x - 9 + 3x C) 9x - 3 +
AlexFokin [52]
These problems really aren't hard just set them equal to each other and see if what they are saying is true. Are they equal? Do they both equal 0?

8 0
3 years ago
Read 2 more answers
Use the Law of Sines to find the measure of angle J to the nearest degree.
rjkz [21]
\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
8 0
3 years ago
Write the solution to the given inequality in interval notation.
Vikentia [17]

Answer:

The answer should be C.

7 0
3 years ago
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