Which graph has a rate of change equal to 1-3 in the interval between 0 and 3 on the x-axis

Is the following graph<br> an example of a linear<br> function?<br> Yes<br> No

oksian1 [2.3K]

Answer:

no

Step-by-step explanation:

A linear equation is a straight line.

6 0

3 years ago

Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive

Nostrana [21]

Answer:

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$ = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

$\sum_{k=0}^\infty a(r)^k$

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is $\sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}$

Given series,

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

$=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......$

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

Let

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$ and $t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

Now for $S_n$ ,

$S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......$

$=\sum_{n=0}^\infty9(\frac 17)^n$

It is a geometric series.

The common ratio of $S_n$ is $\frac17$

The sum of the series

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$

$=\frac{9}{1-\frac17}$

$=\frac{9}{\frac67}$

$=\frac{9\times 7}{6}$

=10.5

Now for $t_n$

$t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......$

$=\sum_{n=0}^\infty3(\frac 15)^n$

It is a geometric series.

The common ratio of $t_n$ is $\frac15$

The sum of the series

$t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

$=\frac{3}{1-\frac15}$

$=\frac{3}{\frac45}$

$=\frac{3\times 5}{4}$

=3.75

The sum of the series is $\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

= $S_n+t_n$

=10.5+3.75

=14.25

4 0

3 years ago

John has a map that shows a rectangular park with a circular pond. The scale on the map is 114 cm : 8 yd. On the map, the width

Ivenika [448]

Answer:

The area of the park is 119,966.14 cm if needed to round it would be 119,966 cm.

Step-by-step explanation:

first we would use A=length x width

so a = 614 cm x 212 cm = 130,168 cm

now we find the area of the pond using a= pi x r^2

the diameter is 114 cm so we cut that in half to find the radius which is 57 cm

a = pi x 57^2

a= 3.14 x 3249

a= 10201.86 cm

now we subtract the area of the pond from the whole area

130,168 - 10201.86 = 119,966.14 cm

The area of the park is 119,966.14 cm if needed to round it would be 119,966 cm

4 0

2 years ago

Simplify 6(4x - 3) show work plz

WITCHER [35]

Answer:

24x-18

Step-by-step explanation:

To simplify this we will need to use the distributive property

we can start with

6*4x=24x

then we can do

6*3=18

and since their is a negative sign in the middle that is what we do, so it will be

24x-18

Can I please have brainliest :)

7 0

3 years ago

Read 2 more answers

Find the domain of the function

densk [106]

Answer:

3x - 7 ≥ 0

3x ≥ 7

x ≥ 7/3

D = [7/3 ; ∞[

D = [7/3 ; ∞)

4 0

3 years ago