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Alexandra [31]
3 years ago
9

Taylin buys 5 ounces of tea leaves for $2.35. At this rate, how much money does she need to buy 12 ounces of tea leaves? (second

part) how would you work be different if you were asked how many ounces of tea leaves Taylin could buy with $10?
Mathematics
2 answers:
MissTica3 years ago
7 0

Answer:

see below

Step-by-step explanation:

We can determine how much 12 ounces cost by using ratios

5 ounces       12 ounces

-------------- = -------------------

2.35                 x

Using cross products

5x = 12*2.35

5x = 28.2

Divide each side by 5

5x/5 = 28.2/5

x =5.64

If she has 10 dollars

5 ounces       y ounces

-------------- = -------------------

2.35                 10

5*10 = 2.35y

50 = 2.35y

Divide each side by 2.35

50/2.35 = 2.35y/2.35

21.27659574 =y

She can buy 21.3 ounces

SCORPION-xisa [38]3 years ago
7 0

Answer:

$5.64; 21.3 ounces

Step-by-step explanation:

ounces : $

5 : 2.35

1 : X

X: the rate $ per ounce

1/5 = x/2.35

X = 0.47

a) 12 × 0.47 = 5.64

b) 0.47 = 10/n

n = 10/0.47

n = 21.2765957447

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1)Convert the following binary numbwers into decimal number(only a,b,c,f,i)<br>​
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Answer:

a) 3₁₀

b) 6₁₀

c) 7₁₀

f) 19₁₀

i) 181₁₀

Step-by-step explanation:

<u>Binary to Decimal Conversion (Positional Notation Method)</u>

  • Multiply each digit by the base (2) raised to the power dependent upon the position of that digit in the binary number.
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  • Express the number as a decimal number by placing subscript 10 after it.

For a binary number with 'n' digits:

  • The right-most digit is multiplied by 2⁰
  • The left-most digit is multiplied by \sf 2^{n-1}

For example, to convert the binary number 111001₂ into a decimal:

\begin{array}{ c c c c c c}1 & 1 & 1 & 0 & 0 & 1\\\downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow \\2^5 & 2^4 & 2^3 & 2^2 & 2^1 & 2^0\\\end{array}

Multiply each digit by the base (2) raised to the power as indicated above and sum them:

=(1 \times 2^5)+(1 \times 2^4)+(1 \times 2^3)+(0 \times 2^2)+(0 \times 2^1)+(1 \times 2^0)

= 32+16+8+0+0+1

= 57

Finally, express as a decimal number ⇒ 111001₂ = 57₁₀

<u>Question (a)</u>

\begin{aligned}\implies 11_2 & = (1 \times 2^1)+(1 \times 2^0)\\& = 2+1\\& = 3\end{aligned}

Therefore, 11₂ = 3₁₀

<u>Question (b)</u>

\begin{aligned}\implies 110_2 & = (1 \times 2^2)+(1 \times 2^1)+(0 \times 2^0)\\& = 4+2+0\\& = 6\end{aligned}

Therefore, 110₂ = 6₁₀

<u>Question (c)</u>

\begin{aligned}\implies 111_2 & = (1 \times 2^2) +(1 \times 2^1)+(1 \times 2^0)\\& =4+2+1\\& = 7\end{aligned}

Therefore, 111₂ = 7₁₀

<u>Question (f)</u>

\begin{aligned}\implies 10011_2 & =(1 \times 2^4)+(0 \times 2^3)+ (0 \times 2^2) +(1 \times 2^1)+(1 \times 2^0)\\& =16+0+0+2+1\\& = 19\end{aligned}

Therefore, 10011₂ = 19₁₀

<u>Question (i)</u>

\phantom{)))}10110101_2 \\\\=(1 \times 2^7)+(0 \times 2^6)+(1 \times 2^5)+(1 \times 2^4)+(0 \times 2^3)+ (1 \times 2^2) +(0 \times 2^1)+(1 \times 2^0)\\\\=128+0+32+16+0+4+0+1\\\\= 181

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