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ira [324]
3 years ago
10

Im thin but wide long and easily ripped im used to draw i lay around until im in a book but not only new

SAT
1 answer:
Alex17521 [72]3 years ago
7 0
I believe the answer is a book... It's thin and long, wide on the sides, easily ripped, etc
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Question 5 of 10
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A. I believe would be your answer
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What mass of glucose (C6H12O6) should be dissolved in 12. 0 kg of water to obtain a solution with a freezing point of -5. 8 ∘C?.
bogdanovich [222]

The mass of glucose solute dissolved in the solution is 6.739 Kg.

Recall that;

ΔT = K m i

ΔT = Freezing point depression

K =Freezing point depression constant = 1.86°C/mol

m = molality of the solution

i = Van't Hoff factor = 1 (molecular solution)

We have to find the freezing point depression from;

Freezing point depression = Freezing point of pure solvent - Freezing point of solution

Freezing point of pure water = 0°C

Freezing point of solution = -5. 8 ∘C

Freezing point depression = 0°C - (-5. 8 ∘C) = 5. 8 ∘C

Now;

m = ΔT/K i

m = 5. 8 ∘C/ 1.86°C/mol × 1

m = 3.12 m

But molality = number of moles of solute/mass of solvent in Kg

Molar mass of solute = 180 g/mol

Let the mass of solute be m

3.12 = m/180/12

3.12 = m/180 × 12

m = 3.12 × 180 × 12

m = 6739 g or 6.739 Kg

Learn more: brainly.com/question/6249935

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There are
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The answer is 1/639, since there are 639 chips, and only one of them is 539.

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