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Vadim26 [7]
4 years ago
10

Most insurance companies will replace a vehicle any time an estimated repair exceeds 80% of the blue book value of the vehicle.

Michele’s insurance company paid $8500 for repairs on her car after an accident. What can be concluded about the blue book value of the car?
Mathematics
1 answer:
nordsb [41]4 years ago
3 0

Answer:

x ≤ 10,625

Step-by-step explanation:

$8500 must be less than or equal to  80% of the blue book value

We can write the following inequality:-

0.80x  ≤ 8500  

x ≤  10,625 where x is the blue book value

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4 0
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Tickets to a dance performance cost $9 for adults and $5 for kids. A group purchased 15 tickets and spent a total of $91. How ma
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Answer:9 adult tickets and 2 kid tickets

Step-by-step explanation:

5 0
3 years ago
A sphere is inscribed in a cube, and the cube has a surface area of 24 square meters. A second cube is then inscribed within the
snow_tiger [21]

Check the picture below, I'll be referring to the material in the picture.

we know the outer cube has a surface area of 24, we also know is a cube, so it has 6 equal sides which are squares each, let's say the side of one of those squares in the cube is say of length "s", so the area of one square will just be  s², and for 6 squares that'll be an area of 6s², that is the area of the outer cube, which we know is 24.

24=6s^2\implies \cfrac{24}{6}=s\implies 4=s^2\implies \sqrt{4}=s\implies 2=s

now, we know the sphere is inscribed in the outer cube, so it's touching its edges, like you see in the picture in blue, so if we get a cross-section of the whole lot, we'd get the picture to the right of blue cube in the picture, an outer cube with a side of 2, and therefore an sphere with a diameter of 2, and thus a radius of 1, as you can see in the red triangle.

Let's notice that the red triangle is a 45-45-90 triangle, and thus we can use the 45-45-90 rule to get its sides, as you can see in the picture on the far-right, which gives us half of one side of the inner cube to be 1/√2.

\stackrel{\textit{half a side}}{\cfrac{1}{\sqrt{2}}}\qquad \stackrel{\textit{a full side}}{\cfrac{1}{\sqrt{2}}+\cfrac{1}{\sqrt{2}}}\implies \cfrac{2}{\sqrt{2}}\implies \cfrac{2\sqrt{2}}{\sqrt{2}\sqrt{2}}\implies \cfrac{2\sqrt{2}}{2}\implies \sqrt{2}

now as you can see in the picture, the inner cube in orange, has 6 sides, each side is √2 long, so let's get the 6 squares area.

\stackrel{\textit{area of one square}}{\sqrt{2}\cdot \sqrt{2}\implies 2}\qquad \stackrel{\textit{area of all 6 sides of the inner cube}}{6\cdot 2\implies 12}

6 0
2 years ago
3(2y + 1) +4<br> Solve this?!!!
grin007 [14]

Multiply the bracket by 3

6y+3+4

Then add 3+4

6y+7

Answer is 6y+7

4 0
3 years ago
Read 2 more answers
Write three equations whose graphs are the same line as the equation 3x+2y=7
babunello [35]
Answer: y=(-3x+7)/2
Isolate y.

2y= -3x+7

y= (-3+7)/2

Answer: x=(-2y+7)/3

Isolate x

3x=-2y+7

x=(-2y+7)/3

Answer: 6x+4y=14
Idk if that counts but multiply the whole equation by 2.
4 0
4 years ago
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