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adelina 88 [10]
2 years ago
15

Locate the b term in the equation.

Mathematics
1 answer:
valentinak56 [21]2 years ago
8 0

Answer:

i can't help but good luck!!

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F(x)=4x+2 find f(8)
JulsSmile [24]

Answer:

34

Step-by-step explanation:

Substitute 8 where there is an x

f (8)= 4(8) +2

= 32 +2

=34

8 0
3 years ago
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How do I change z= -14+ 8i from rectangular form to polar form?
Olenka [21]
The answer will be z=-6 because 16-8=6
3 0
3 years ago
3x 3/5 help me please
ser-zykov [4K]

Answer:

9/5

Step-by-step explanation:

it is because 3/1 × 3×5

so which means 9/5

8 0
2 years ago
Read 2 more answers
PLS ANSWER URGENT
san4es73 [151]
A) The given equation has no solution. The absolute value cannot be negative, but must be -9 in order for the equation to be satisfied.


b) |x -7| = 2 . . . . . . . the equation
Solution 1:
  -2 = x -7
  5 = x . . . . . . add 7
Solution 2
  x -7 = 2
  x = 9 . . . . . . add 7

The two numbers are {5, 9}
8 0
3 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
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