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jasenka [17]
3 years ago
9

Steve claims that the sun of two off numbers is always even. How can Steve prove his conjecture?

Mathematics
2 answers:
Elodia [21]3 years ago
7 0

Answer:

Show one example of his claim, adding two odd numbers to form an even number

Alisiya [41]3 years ago
5 0

Answer:

C.

Step-by-step explanation:

You cannot prove his conjecture by an example. You must create two generic odd numbers using algebraic expressions. Then you add the two expressions and show that the sum is even.

Answer: C.

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2.5 cm is the radius

Step-by-step explanation:

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3 years ago
The sum of the arithmetic progression 4, ..., 76 is 1920. Find the number of terms and the common difference.​
valkas [14]

<u>Number of terms = 48</u>

<u>common difference = 1.5</u>

This question involves the concept of Arithmetic Progression.

  • The formula for sum of an arithmetic progression series with first and last term given is;

S_{n} = \frac{n}{2}(a + l)

where;

a = first term

l = last term

n = number of terms

  • From the given sequence, we see that;

first term; a = 4

last term; l = 76

Sum of A.P; S_{n} = 1920

  • Plugging in relevant values into the sum of an AP formula, we have;

1920 = \frac{n}{2}(4 + 76)

simplifying this gives;

1920 = 40n

n = 1920/40

n = 48

  • Formula for nth term of an AP is;

t_{n} = a_{1} + (n - 1)d

where;

a_{1} is first term

d is common difference

n is number of term

t_{n} is the nth term in question

the 48th term is 76

Thus;

76 = 4 + (48 - 1)d

76 - 4 = 47d

72 = 47d

d = 72/47

d ≈ 1.5

Thus;

Number of terms = 48

common difference = 1.5

Read more at; brainly.com/question/16935540

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Find the radius of a sphere whose surface area is 154cm².​with stepss
worty [1.4K]

Answer:

THIS IS YOUR ANSWER:

area \: of \: spere \:  = 4\pi \: r {}^{2}  \\ 154cm {}^{2} = 4 \times  \frac{22}{7}  \times r {}^{2}

\frac{154 \times 7}{4 \times 22} = r {}^{2} \\ r {}^{2} = 12.25 \\

r =  \sqrt{12.25} \\ r = 3.5cm

<em>✍️</em><em>HOPE</em><em> </em><em>IT HELPS</em><em> </em><em>YOU</em><em> </em><em>✍️</em>

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2 years ago
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