1) 3x+y+z=4
2) 2x+2y+3z=3
3) x+3y+2z = 5
1)*2 6x + 2y + 2z = 8
2) 2x + 2y +3z = 3
- __________________
4x - z = 5
2)*3 6x + 6y + 9z = 9
3)*2 2x + 6y + 4z = 10
- __________________
<span>4x+5z =-1
</span>
4x+5z = -1
4x - z =5
- ________
6z = -6
<u>z = -1
</u><u /><u>
</u>If z=-1,
4x -(-1) =5
4x = 5-1
x = 4/4
<u>x=1</u>
3x+y+z=4
3(1)+y+(-1)=4
3+y-1=4
<u>y=2
So z=-1, x=1, y=2</u>
I think the answer you are looking for is 1
<u><em>NOT AT ALL 100% SURE :(</em></u>
N*3.25=325.00
N=325.00/3.25
N=100
Answer:
Kylie could have a $5 bill and seven quarters while Ethan could have two $1 bills and forty pennies.
Step-by-step explanation:
Since Kylie has seven quarters, that is seven multiplied by the value of the quarter, a quarter is 25 cents. So 7 x 25 = 125 OR $1 and 25 cents. Leaving Kylie with a total of $7 and 25 cents with the addition of the $5 bill.
Ethan has two $1 bills and forty pennies, forty multiplied by the value of the penny, a penny is 1 cent. So 40 x 1 = 40 OR 40 cents. Leaving Ethan with $2 and 40 cents with the addition of the two $1 bills from earlier.
Ethan has more bills and coins than Kylie and yet still has less money than Kylie.
