Question

An epidemic has hit Minecole City. Its population is declining 34% every hour. In just 3 hours, there are only 25,143 people left in the city. What was the initial population in the city before the epidemic broke out?

Answer 1

Answer:

The initial population in the city before the epidemic broke out was 87455.

Step-by-step explanation:

The decay formula is:  $A=P(1-r)^t$ , where $P=$ Initial amount, $A=$ Final amount, $r=$ rate of decay in decimal form and $t=$ time duration.

Here, $A=25143,\ \ r=34\%=\frac{34}{100}=0.34,\ \ t=3\ hours$

Plugging these values into the above formula.....

$25143=P(1-0.34)^3\\ \\ 25143=P(0.66)^3\\ \\ 25143=P(0.287496)\\ \\ P=\frac{25143}{0.287496}=87455.129...\approx 87455$

So, the initial population in the city before the epidemic broke out was 87455.