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pogonyaev
3 years ago
5

20 pts !!

Mathematics
2 answers:
satela [25.4K]3 years ago
6 0
It’s C have a great day
Ivahew [28]3 years ago
5 0
The answer is C)

Step-by-step explanation:
4x(x+1) - (3x-8)(x+4)
(4x^2+4x) - (3x^2+12x-8x-32)
(4x^2+4x - 3x^2-12x+8x+32)
4x^2-3x^2+4x+8x-12x+32
=x^2+32
Quadratic binomial
You might be interested in
3x over 2x-6 plus 9 over 6-2x
Mars2501 [29]
Answer: 3/2
Explanation:
3x/2x-6 + 9/6-2x
= 3x/2x-6 + 9/-(2x+6)
= 3x/2x-6 + -9/2x-6
= 3x/2x-6 - 9/2x-6
= 3x - 9/2x-6
= 3(x-3)/2(x-3) (cancel out x-3)
= 3/2


7 0
3 years ago
Read 2 more answers
the formula for the circumference (c) of a circle is c= 2πr. calculate c if r=0.8695 mm, keeping the highest possible number of
Marianna [84]

The value of the circumference (C) of a circle, having a radius (r) = 0.8695 mm, using the formula C = 2πr, is calculated to be <u>5.4632296245926504416865368435231‬ mm</u>.

A circle is a shape formed by all points in a plane that are at a particular distance from the center.

The linear distance around a circle is defined as its circumference. In other words, if a circle is opened to produce a straight line, the length of that line equals the circumference of the circle.

The formula for the circumference of a circle is given:

C = 2πr,

where C is the circumference of the circle, r is its radius, and π is a constant.

We are asked to find the circumference of the circle (C), given its radius (r) = 0.8695 mm.

Using the formula of the circumference C = 2πr, we can find the circumference as:

C = 2*π*(0.8695) mm,

or, C = 5.4632296245926504416865368435231‬ mm.

Thus, the value of the circumference (C) of a circle, having a radius (r) = 0.8695 mm, using the formula C = 2πr, is calculated to be <u>5.4632296245926504416865368435231‬ mm</u>.

Learn more about the circumference of a circle at

brainly.com/question/12823137

#SPJ1

6 0
1 year ago
Maurice and Johanna have appreciated the help you have provided them and their company Pythgo-grass. They have decided to let yo
Colt1911 [192]
<span><span>1.A triangular section of a lawn will be converted to river rock instead of grass. Maurice insists that the only way to find a missing side length is to use the Law of Cosines. Johanna exclaims that only the Law of Sines will be useful. Describe a scenario where Maurice is correct, a scenario where Johanna is correct, and a scenario where both laws are able to be used. Use complete sentences and example measurements when necessary.
</span>
The Law of Cosines is always preferable when there's a choice.  There will be two triangle angles (between 0 and 180 degrees) that share the same sine (supplementary angles) but the value of the cosine uniquely determines a triangle angle.

To find a missing side, we use the Law of Cosines when we know two sides and their included angle.   We use the Law of Sines when we know another side and all the triangle angles.  (We only need to know two of three to know all three, because they add to 180.  There are only two degrees of freedom, to answer a different question I just did.

<span>2.An archway will be constructed over a walkway. A piece of wood will need to be curved to match a parabola. Explain to Maurice how to find the equation of the parabola given the focal point and the directrix.
</span>
We'll use the standard parabola, oriented in the usual way.  In that case the directrix is a line y=k and the focus is a point (p,q).

The points (x,y) on the parabola are equidistant from the line to the point.  Since the distances are equal so are the squared distances.

The squared distance from (x,y) to the line y=k is </span>(y-k)^2
<span>
The squared distance from (x,y) to (p,q) is </span>(x-p)^2+(y-q)^2.<span>
These are equal in a parabola:

</span>
(y-k)^2 =(x-p)^2+(y-q)^2<span>

</span>y^2-2ky + k^2 =(x-p)^2+y^2-2qy + q^2

y^2-2ky + k^2 =(x-p)^2 + y^2 - 2qy+ q^2

2(q-k)y =(x-p)^2+ q^2-k^2

y = \dfrac{1}{2(q-k)} ( (x-p)^2+ q^2-k^2)

Gotta go; more later if I can.

<span>3.There are two fruit trees located at (3,0) and (−3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the y-axis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane.

4.A pipe needs to run from a water main, tangent to a circular fish pond. On a coordinate plane, construct the circular fishpond, the point to represent the location of the water main connection, and all other pieces needed to construct the tangent pipe. Submit your graph. You may do this by hand, using a compass and straight edge, or by using a graphing software program.

5.Two pillars have been delivered for the support of a shade structure in the backyard. They are both ten feet tall and the cross-sections​ of each pillar have the same area. Explain how you know these pillars have the same volume without knowing whether the pillars are the same shape.</span>
5 0
4 years ago
Consider the matrix shown below:
balu736 [363]

Answer:

Its Not C or B, tried em and got em wrong

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Differentiate the following function.<br> y=x(x^2+5)^2
dalvyx [7]
First, expand to make it easier
y=x(x^2+5)(x^2+5)
y=x(x^4+10x^2+25)
y=x^5+10x^3+25x
differentiation
y'=5x^4+30x^2+25 is the derivitive
8 0
3 years ago
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