Question

Which pair shows equivalent expressions?

Answer 1

Answer:

Option 3

Step-by-step explanation:

We need to find a pair which shows equivalent expressions.

First equation is

$2x+10=-2(x-5)$

$LHS=2x+10$

$RHS=-2(x-5)=-2(x)-2(-5)=-2x+10$

$LHS\neq RHS$

Option 1 is incorrect.

Second equation is

$-2(x+5)=2x-10$

$LHS=-2(x+5)=-2(x)-2(5)=-2x-10$

$RHS=2x-10$

$LHS\neq RHS$

Option 2 is incorrect.

Third equation is

$-2x-10=-2(x+5)$

$LHS=-2x-10$

$RHS=-2(x+5)=-2(x)-2(5)=-2x-10$

$LHS=RHS$

Option 3 is correct.

Fourth equation is

$-2(x–5)=-2X-10​$

$LHS=-2(x–5)=-2(x)-2(-5)=-2x+10$

$RHS=-2x-10$

$LHS\neq RHS$

Option 4 is incorrect.

Therefore, the correct option is 3.