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3 years ago

Least common multiple of 11,39,35,8

2 answers:

5 0

Factor each out:
11: 1*11
39: 3*13
35: 5*7
8: 2*2*2
since you can see no common factor just multiply them all to get 120120

Harlamova29_29 [7]3 years ago

4 0

Least Common Multiples (LCM) of 11,39,35, and 8 is 120120

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Caroline has some dimes and some quarters. She has a maximum of 15 coins worth at least $2.85 combined. If Caroline has 3 dimes,

gayaneshka [121]

Answer:

11, 12.

Step-by-step explanation:

Let q represent number of quarters.

We have been given that Caroline has a maximum of 15 coins worth at least $2.85 combined. We are also told that Caroline has 3 dimes. This means that total coins are less than or equal to 15.

We can represent this information in an inequality as:

$q+3\leq 15...(1)$

We are also told that the coins worth at least $2.85 combined. This means that the worth of all coins is greater than or equal to 2.85.

We know that each dime is worth $0.10 and each quarter is worth $0.25.

$0.25q+3(0.10)\geq 2.85...(2)$

Now, let us solve our system of inequalities.

From 1st inequality, we will get:

$q+3-3\leq 15-3$

$q\leq 12$

From 2nd inequality, we will get:

$0.25q+0.30\geq 2.85$

$0.25q+0.30-0.30\geq 2.85-0.30$

$0.25q\geq 2.55$

$\frac{0.25q}{0.25}\geq \frac{2.55}{0.25}$

$q\geq 10.2$

Upon combining our both inequalities, we will get:

$10.2\leq q\leq 12$

This means that numbers of quarters would be greater than or equal to 10.2 and less than or equal to 12.

Since we cannot have 0.2 of a coin, therefore, Caroline could have 11 or 12 quarters.

6 0

3 years ago

Use geometric series to find the fraction of 0.8967898989

Sliva [168]

I'm guessing the repeating part is 89 at the end, so that

$x=0.8967\overline89\implies10^4x=8967.\overline{89}$

Then

$10^4x=8967+\displaystyle89\sum_{i=1}^\infty\frac1{100^i}$

$10^4x=8967+89\left(\dfrac1{1-\frac1{100}}-1\right)$

$10^4x=8967+\dfrac{89}{99}$

$x=\dfrac{8967}{10^4}+\dfrac{89}{99\cdot10^4}$

$x=\dfrac{443911}{495000}$

###

An arguably quicker way without using geometric series:

$10^4x=8967.\overline{89}$

$10^6x=896789.\overline{89}$

$10^6x-10^4x=887822$

$x=\dfrac{887822}{10^6-10^4}=\dfrac{443911}{495000}$

8 0

3 years ago

A man cut his 2 fingers and add 4 hands with 7 fingers. And he also chop his leg 3 times everyday till January to December. How

Olenka [21]

Answer: 30

Step-by-step explanation:

10 is the started fingers of the hands

2 is fingers, 4 are the hands, 7 the fingers of the hands

2 + (4 · 7) = 30

-3 is the legs per day, and 365 are the days per year

-3 · 365 = -1095

this is a bizarre question

4 0

3 years ago

How to solve math word problems

Rina8888 [55]

Read the question and then answer it.
you could try highlighting key parts so you understand it more

5 0

3 years ago

The graph below shows the relationship between the number of months different students practiced boxing and the number of matche

yulyashka [42]

Part A: The y-intercept of the line of best fit is about 4. This represents the starting point, or figure 0.

Part B: Using the line, you could determine that the slope is about 3/2, or 1.5, and the 13th month would be at about 24 matches.

Equation: y=4x+1.5

Hope this helps,

LaciaMelodii :)

5 0

3 years ago

Read 2 more answers