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Stolb23 [73]
4 years ago
5

A cylinder has a radius of 6 inches and the height of 15 what is the surface area of the cylinder

Mathematics
1 answer:
wel4 years ago
5 0

Answer:

792 inches squared.

Step-by-step explanation:

hope this helps!

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Explain to me in words how you would find the slope of this line
Alchen [17]

Answer:

3

Step-by-step explanation: From one point, go over to the top/bottom of the other point then go down/up to the point (go from one point to the other) then the rise you did (1) over the run across (3) then the formula is rise over run. then divide.

3 0
3 years ago
The federal government requires a car manufacturer to have a minimum miles per gallon (mpg) average over the models it makes. Su
valentinak56 [21]

Answer:

25 mpg

Step-by-step explanation:

We have a set of values 19, 21, 22, 28  and 18  

The average (which is the mean of the set of values )  is :

19 + 21 + 22 + 28 + 18 = 21.6 mpg   out of the government requirement

So we need a value such as the mean become at least 25 mpg

We have to solve the equation:

(19+21+22+28+ x)/ 5  = 25

 (90 + x ) /5  = 25       ⇒   90 + x = 125   ⇒   x = 35 mpg

If we get the mean of the set of values including 35 we have:

(19 +21+ 22+ 28 + 35 ) / 5   =  25 mpg  government requirement

7 0
3 years ago
What additional information is needed that the following triangle are congruent by SSS
Svet_ta [14]

Answer:

Side ACwith DF

Step-by-step explanation:

7 0
3 years ago
20 divided by 2 (5+5)=
AveGali [126]
<span>The correct answer is 1.

Explanation:
The way this is written, everything after the words "divided by" would be calculated first; it is written as though this is a grouping, such as 20/(2*(5+5)). We would evaluate the innermost parentheses first; 5+5=10. Then this gives us 2*10=20 in our parentheses. 20/20 = 1.</span>
6 0
3 years ago
Which expression is equivalent to sec^2xcot^2x?
Lady_Fox [76]
\sec x=\dfrac{1}{\cos x}\\\\\cot x=\dfrac{\cos x}{\sin x}


\sec^2x\cot^2x=\dfrac{1}{\cos^2x}\cdot\dfrac{\cos^2x}{\sin^2x}=\dfrac{\cos^2x}{\cos^2x\sin^2x}=\dfrac{1}{\sin^2x}
8 0
3 years ago
Read 2 more answers
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