Answer:
The answer is 9x+12
Step-by-step explanation:
You can't add a number with a variable to a number without a variable.
In this question, we have to find the algebraic expression of Six less than the square of the sum of 5 and a number.
And here the number is x.
Sum of 5 and a number x is represented as
And the square of sum of 5 and the number x is
And finally it is six less than the expression we got above, that is
Therefore out of the four options, correct option is A .
Answer:
Step-by-step explanation:
given that a bacteria culture initially contains cells and grows at a rate proportional to its size.
If P be the size then growth rate
where k is constant of proportionality
separate the variables as
If after 1 hour population is B (say)
then k = ln B - ln A
Using this
P(t) =
b) P(e) =
c) Rate of growth =
Unless you give B value, d cannot be solved
Answer:
Set 1 Angle A is 90
Set 1 Angle B is 45
Set 2 Angle B is 15
Set 2 Angle C is 90
2)
Set 1 Angles A and C are both 62
Set 2 Angles B and D are both 120
Step-by-step explanation:
The <em>correct answer</em> is:
x < 17.89 or x > 18.61 because |x – 18.25| > 0.36
.
Explanation:
We know that the target weight is 18.25. We also know that to be accepted, the weight of each pack must be within 0.36 of this target weight. The packs can be up to 0.36 more than or up to 0.36 less than the target weight; for this reason, we use an absolute value equation:
|x-18.25| ≤ 0.36
However, we are concerned with the weights of the packs that are rejected. These will be <em>more than </em>0.36 different from the target weight:
|x-18.25| > 0.36
To solve this, we consider the positive and negative values of 0.36 (since it is an absolute value equation). Remember the rules of inequalities; when we change the sign of the answer, we change the inequality sign as well:
x - 18.25 > 0.36 or x - 18.25 < -0.36
To solve each of these, add 18.25 to each side:
x - 18.25 + 18.25 > 0.36 + 18.25 or x - 18.25 + 18.25 < -0.36 + 18.25
x > 18.61 or x < 17.89
This means the correct choice is the first one.