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zavuch27 [327]
3 years ago
11

Which ordered pair is a solution to the system of equations shown in the graph below?

Mathematics
1 answer:
Blizzard [7]3 years ago
5 0
(5,7) is the answer to the question, you can also use (-1,-5)
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A number a decreased by 7 is 2.
umka21 [38]

Answer:

9

Step-by-step explanation:

Let's first convert this to numbers. When a number is decreased by a certain amount, that is the same as saying that something is subtracted from it. Therefore:

a-7=2

Add 7 to both sides:

a-7+7=2+7

a=9

Hope this helps!

7 0
3 years ago
Read 2 more answers
solve for x. round your answer to two decimal places. show your work for full credit. a right triangle is shown with the hypoten
Molodets [167]
I hope this helps you

3 0
3 years ago
A spinner is numbered 1-10. What is the probability of the spinner landing on the number 5 on the first spin and an even number
Deffense [45]

Answer:

10% and 50%

Step-by-step explanation:

5 0
3 years ago
How many centimeters are in 6.8 meters?
sesenic [268]

Answer:

680 cm

Step-by-step explanation:

There are 100 cm in 1 m, so multiply 6.8*10, which equals 680

hope this helps :)

7 0
3 years ago
The graph of f ′ (x), the derivative of f(x), is continuous for all x and consists of five line segments as shown below. Given f
Nataliya [291]

The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.

Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.

By the fundamental theorem of calculus,

\displaystyle f(5) = f(0) + \int_0^5 f'(x) \, dx

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so

\displaystyle \int_0^5 f'(x) \, dx = \frac{5+2}2 \times 2 = 7

\implies \max\{f(x) \mid 0\le x \le5\} = f(5) = f(0) + 7 = \boxed{13}

8 0
3 years ago
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