12n - 8- 2n + 10

The minimum wage in 2003 was $5.15. This was w more than the minimum wage in 1996. Write an expression for the minimum wage in 1

bekas [8.4K]

$5.15 - w = minimum wage in 1996

(if that wasn't what you were looking for then comment what you really wanted)

8 0

3 years ago

Tommy has 6 more than 3 times the amount of money in his bank account than Judy. Judy has $7500 more than a number in her accoun

balu736 [363]

Answer: Judy: n+7500

Tommy: 3(n+7500)+6

Step-by-step explanation:

4 0

3 years ago

Let’s assume that human body temperatures are normally distributed with a mean of 98.20° F and a standard deviation of 0.62° F.

uysha [10]

Answer: It is such a small percentage of the population that would be considered to have fever at that level.

So, it is not appropriate stringent standard.

Step-by-step explanation:

Since we have given that

Mean = 98.20°F

Standard deviation = 0.62°F

If Bellevue Hospital in New York City uses 100.6°F as the lowest temperature considered to be a fever.

So, $\bar{X}=100.6^\circ F$

So, using the normal distribution, we first find the value of z.

$z=\dfrac{\bar{x}-\mu}{\sigma}\\\\x=\dfrac{100.6-98.2}{0.62}\\\\z=3.87$

Since z = 3.87

So, p = 0.0001 =0.1%

So,It is such a small percentage of the population that would be considered to have fever at that level.

So, it is not appropriate stringent standard.

4 0

3 years ago

A quickie. If n identical dice are rolled, number of possible outcomes are?

nata0808 [166]

In rolling one die, there are 6 possible outcomes because each die has 4 faces. The number of outcomes when rolling n dice is equal to 6^n. By this, the number of outcomes when 2 dice are rolled is 36, 216 for 3 dice, and so on.

4 0

3 years ago

Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat

eimsori [14]

Answer:

There are NO real roots for this equation. The only roots have imaginary parts and therefore cannot be represented on the real x-axis.

Step-by-step explanation:

We notice that the expression on the left of the equation is a quadratic with leading term $2x^2$ , which means that its graph is that of a parabola with branches going up.

Therefore, there can be three different situations:

1) if its vertex is ON the x axis, there would be one unique real solution (root) to the equation.

2) if its vertex is below the x-axis, the parabola's branches are forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will have NO real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently.

We recall that the x-position of the vertex for a quadratic function of the form $f(x)=ax^2+bx+c$ is given by the expression:

$x_v=\frac{-b}{2a}$

Since in our case $a=2$ and $b=-3$ , we get that the x-position of the vertex is:

$x_v=\frac{-b}{2a}\\x_v=\frac{-(-3)}{2(2)}\\x_v=\frac{3}{4}$

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = 3/4:

$y_v=f(\frac{3}{4})=2( \frac{3}{4})^2-3(\frac{3}{4})+4\\f(\frac{3}{4})=2( \frac{9}{16})-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{18}{8}+\frac{32}{8}\\f(\frac{3}{4})=\frac{23}{8}$

This is a positive value for y, therefore we are in the situation where there is NO x-axis crossing of the parabola's graph, and therefore no real roots.

We can though estimate a few more points of the parabola's graph in order to complete the graph as requested in the problem. For such we select a couple of x-values to the right of the vertex, and a couple to the right so we can draw the branches. For example: x = 1, and x = 2 to the right; and x = 0 and x = -1 to the left of the vertex:

$f(-1) = 2(-1)^2-3(-1)+4= 2+3+4=9\\f(0)=2(0)^2-3(0)+4=0+0+4=4\\f(1)=2(1)^2-3(-1)+4=2-3+4=3\\f(2)=2(2)^2-3(2)+4=8-6+4=6$

See the graph produced in the attached image.

4 0

3 years ago

12n - 8- 2n + 10 - 4