Answer:
(D) y³ - 8y² +8y +5
Step-by-step explanation:
y³ - 6y²+ 5y - (2y²- 3y - 5 ) = y³ - 6y² + 5y - 2y² + 3y +5 = y³ - 8y² +8y +5
Answer:
See below.
Step-by-step explanation:
Again, another great question!
This should be under physics, as it involves Work = Force * Distance. As Anne pushes the wheelbarrow with a force of 70 Newtons with respect to an angle of 50 degrees horizontal, the horizontal force is 70( cos 50 ). The distance over which the work is done is 25 meters, so work should be -
Work = ( 70( cos 50 ) )( 25 ),
Work = ( About ) 1124.87 Joules
<u><em>The work done when Anne pushes the wheelbarrow a distance of 25 meters, is 1124.87 Joules</em></u>
X+
=12
5x=36
x=7.2
So, the triangular entrance to the tent is
7.2 feet tall and
4.8 feet wide
Sin30= opposite/hypotenuse
sin30= AC/10
AC= 4.5cm
Tan25= opposite/adjacent
Tan25= 4.5/ CD
CD= 10.7
Answer:
x = -1
, y = 1
Step-by-step explanation:
Solve the following system:
{5 x + 3 y = -2 | (equation 1)
3 x + 2 y = -1 | (equation 2)
Subtract 3/5 × (equation 1) from equation 2:
{5 x + 3 y = -2 | (equation 1)
0 x+y/5 = 1/5 | (equation 2)
Multiply equation 2 by 5:
{5 x + 3 y = -2 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{5 x+0 y = -5 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 5:
{x+0 y = -1 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer: {x = -1
, y = 1
