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3 years ago

Find the perimeter of the following isosceles triangle

Mathematics

1 answer:

AlladinOne [14]3 years ago

4 0

Just add all the sides its really easy i would have done it but i cant see the squares that are on the paper or pc idk

Hope that helped!

if it didnt help just let me know and ill hlp you even more !

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If the perimeter of a triangle is 31 ft and two of the side lengths are 15 ft and 10 ft, what is the length of the third side?

erastovalidia [21]

Answer:

C) 6 ft

Step-by-step explanation:

Perimeter is just adding the side lengths together so...

31-15-10=x

6=x

so your answer is 6ft

3 0

2 years ago

Read 2 more answers

Number 15 please help 10 points no links pleAse

Kazeer [188]

Answer:

C

Explanation:

On the scatter plot, there is a dot where the lines for 6 and 3 meet. when looking for the ordered pair you would go along first then up (> then ^) so it would be (6,3). Another example, for the third dot on the plot, if you go along first you get 12 then when you go up you get 9 so the ordered pair for that would be (12,9). I really hope you understand what i mean and this helps as i struggled with explaining haha!

8 0

2 years ago

You are given g(x)=4x^2 + 2x and

Strike441 [17]

Answer:

324

Step-by-step explanation:

Given:

$g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt$

Find:

$f(6)$

First, find f(x):

$f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2$

Now,

$f(6)\\ \\=\dfrac{4\cdot 6^3}{3}+6^2\\ \\=288+36\\ \\=324$

4 0

3 years ago

Which number is composite 2, 5, 11, 9,

kykrilka [37]

Answer:

Step-by-step explanation:

3*3 =9

4 0

2 years ago

Which explains how to find the quotient of the division below? Negative 3 and one-third divided by StartFraction 4 over 9 EndFra

Ulleksa [173]

Answer:

(B) Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 7 and StartFraction 6 over 12 EndFraction = Negative 7 and one-half.

Step-by-step explanation:

To find the quotient of the division:

$-3\dfrac13 \div \dfrac49$