Answer:
There are all true statements
Step-by-step explanation:
the graph is just trying to confuse you but it's simple just find the letters on the graph then see if they look how the show it below
6 bc if you divide 56 by 9 you’ll get 6.2 but i’m not sure the ( .2 ) will matter therefore just get the first digit which is 6
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
Answer:
See below.
Step-by-step explanation:
5a)
In an isosceles triangle, the angles opposite the congruent sides are congruent.
m<A = 40 deg
m<B = 40 deg
m<A + m<B + m<C = 180
40 + 40 + m<C = 180
m<C = 100 deg
5b)
In a right triangle, one angle is a right angle.
m<A = 40 deg
m<B = 90 deg
m<A + m<B + m<C = 180
40 + 90 + m<C = 180
m<C = 50 deg
