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uysha [10]
3 years ago
15

If (ax^2 + 3x + 2b) - (5x^2+bx-3c)=3x^2-9, what is the value of A + B + C?

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:

We have the equation:

(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

This must be zero for all the values of x, then the things inside each parenthesis must be zero.

1)

a - 5 - 3 = 0

a = 3 + 5 = 8.

2)

3 - b = 0

b = 3.

3)

2b + 3c + 9 = 0

2*3 + 3c + 9 = 0

3c = -6 - 9 = -15

c = -15/3 = -5

Then we have:

a = 8, b = 3, c = -5

a + b + c = 8 + 3 - 5 = 6

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3 years ago
What is the first step to simplify the expression 64^42-[2(4-6)2]?
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2 years ago
Which mixed number is equivalent to the improper function below? 46/10
Valentin [98]

Answer:

B. 4 and 6/10

Step-by-step explanation:

in order to find this answer i've always had a trick where i first off find an even number to divide these with and in this case that would be 4 and then the leftovers would be 6/10 and in this case your answer would be right there 4 and 6/10 but if needed to be simplified it would be 4 and 3/5

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Answer:

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Step-by-step explanation:

To solve this problem we will use the formula to find the slope of a line given two points (x₁, y₁), (x₂, y₂)

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So, we're going to use the points (2,5), (-3, -2) in this formula.

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