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Juliette [100K]
3 years ago
9

Over a period of 12 weeks, Carlos ran an average of 21 miles per week. How many kilometers is this? Round your answer to the nea

rest hundredth. (1 km = 0.621 mi.)
405.80
13.04
33.82
156.49
Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

405.80

Step-by-step explanation:

So, we know Carlos ran 21 miles per week, for 12 weeks....

That makes 21 mi/wk x 12 weeks = 252 miles.

Then we know each km is 0.621 mile.

So, we divide 252 miles by 0.621 mile/km to get= 405.80 km

Dividing miles by miles/km gives us the unit we want (km).

<u>There was a trap in this question,</u> because if instead of dividing the 252 miles by 0.621 you would have multiplied it, you would have gotten another answer listed... just not the right one. :-)

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Which of the following sets of ordered pairs satisfies a linear function? a. (-1,5), 2,10), (3,15), (4,18), (5,22) b. (2,4), (4,
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−2x = 4y + 6 2(2y + 3) = 3x − 5 What is the solution (x, y) to the system of equations above
Wewaii [24]

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(1;-2)

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3 years ago
Based on the information given say whether or not △ABC∼△FED. Explain your reasoning.
GalinKa [24]

Answer:

Yes, △ABC ∼ △FED by AA postulate.

Step-by-step explanation:

Given:

Two triangles ABC and FED.

m∠A = m∠B

m∠C = m∠A + 30°

m∠E = m∠F = x

m∠D = 2x-20°.

Now, let m∠A = m∠B = y

So, m∠C = m∠A + 30° = y+30

Now, sum of all interior angles of a triangle is 180°. Therefore,

m∠A + m∠B +  m∠C = 180

y+y+y+30=180\\3y=180-30\\3y=150\\y=\frac{150}{3}=50

Therefore, m∠A = 50°, m∠B = 50° and m∠C =  m∠A + 30° = 50 + 30 = 80°.

Now, consider triangle FED,

m∠D+ m∠E + m∠F = 180

2x-20+x+x=180\\4x=180+20\\4x=200\\x=\frac{200}{4}=50

Therefore,  m∠F = 50°  

m∠E = 50° and  

m∠D =  2x-20=2(50)-20=100-20=80\°

So, both the triangles have congruent corresponding angle measures.

m∠A = m∠F = 50°

m∠B = m∠E = 50°

m∠C = m∠D = 80°

Therefore, the two triangles are similar by AA postulate.

5 0
3 years ago
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