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4 years ago

Marty is explaining to Susan how to solve the following problem, -4 – (-5)

Mathematics

1 answer:

Alexxx [7]4 years ago

4 0

Answer:

The correct answer is:

To subtract an integer, add its opposite; -4 + 5 = 1

Step-by-step explanation:

Marty is explaining to Susan how to solve the following problem, -4 – (-5)

He told Susan that to subtract an integer, add its opposite.

We know that whenever we solve the two terms, first we multiply the signs.

It means that the negative sign outside the round bracket will be multiplied with the negative sign of -5

That is,

-4 - (-5)

By multiplying the signs we get the terms:

-4 + 5

Thus the correct option is D....

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I hope this helps you a=C/8.pi.b

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Which statements describe a residual plot for a line of best fit that is a good model for a scatterplot? Check all that apply. T

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Answer:

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3 years ago

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3 years ago

Can someone please help with this math question:)

Bingel [31]

Solution:

The rationalisation factor for $\frac{1}{ a - \sqrt{b} }$ is $a + \sqrt{b}$

So, let us apply it here.

$\frac{1}{5 - \sqrt{2} }$

The rationalising factor for 5 - √2 is 5 + √2.

Therefore, multiplying and dividing by 5 + √2, we have

$= \frac{1}{5 - \sqrt{2} } \times \frac{5 + \sqrt{2} }{5 + \sqrt{2} } \\ = \frac{5 + \sqrt{2} }{(5 - \sqrt{2})(5 + \sqrt{2} ) } \\ = \frac{5 + \sqrt{2} }{ {(5)}^{2} - ( \sqrt{2})^{2} } \\ = \frac{5 + \sqrt{2} }{25 - 2} \\ = \frac{5 + \sqrt{2} }{23}$

Answer:

$\frac{5 + \sqrt{2} }{23}$

Hope you could understand.

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2 years ago

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Solve for x in the equation 2x^2-4x-9=29

Andrews [41]

Answer:

x = 1 ±2sqrt(5)

Step-by-step explanation:

2x^2-4x-9=29

Add 9 to each each side

2x^2-4x-9+9=29+9

2x^2-4x=38

Divide by 2

2/2x^2-4/2x=38/8

x^2 -2x =19

Complete the square

x^2 -2x + (-2/2)^2 = 19 +(-2/2)^2

x^2 -2x +1 = 19+1

(x-1)^1=2 = 20

Take the square root of each side

sqrt((x-1)^2) = ±sqrt(20)

x-1 = ±sqrt(20)

Add 1 to each side

x-1+1 = 1 ±sqrt(20)

x = 1 ±sqrt(20)

Simplifying the square root of 20

x = 1 ±sqrt(4)sqrt(5)

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3 years ago