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3 years ago

Simplify the radical expression. Show all your steps. √363 - 3√27

Mathematics

1 answer:

siniylev [52]3 years ago

3 0

Answer:

2 sqrt(3)

Step-by-step explanation:

Simplify the following:

sqrt(363) - 3 sqrt(27)

sqrt(27) = sqrt(3^3) = 3 sqrt(3):

sqrt(363) - 33 sqrt(3)

sqrt(363) = sqrt(3×11^2) = 11 sqrt(3):

11 sqrt(3) - 3×3 sqrt(3)

-3×3 = -9:

11 sqrt(3) + -9 sqrt(3)

11 sqrt(3) - 9 sqrt(3) = 2 sqrt(3):

Answer: 2 sqrt(3)

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

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3 years ago

Read 2 more answers

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

1 year ago