Answer:
Sequential
Explanation:
Based on the information provided within the question it can be said that the search algorithm that is being described in this scenario is a Sequential algorithm. This is because sequential programming focuses on programming (or in this case searching for) a result by doing one step at a time as opposed to various functions running simultaneously.
Explanation:
i think cpu needs to have backup chache units in case of electrical failure
Answer:
We need context, it could be several answers
Explanation:
Answer:
(b). dependency and hedging.
Explanation:
In the management of risk, four common approaches for reducing risk are;
i. <em>Avoidance</em>: Especially if a risk involved in the management of a resource (or project) poses or presents a negative consequence, the best way to manage the risk simply avoid it by making sure it doesn't happen. This can be by cancelling a project or restructuring it.
ii. <em>Adaptation</em>: Another way of managing the risk associated with a resource (human or non-human resource) is to control the risk either by increasing resilience or reducing vulnerability. This is called adaptation.
iii. <em>Dependency: </em>This means accepting the risk since every project or business has inherently in it some risk associated. Dealing with it might be a way out especially knowing that there might be some experience to be gained in order to tackle similar situation in the future.
iv. <em>Hedging: </em>This means transferring the risk to some other business or organization. An example might be to get an insurance to manage this risk. In this case, the risk is transferred to the insurance company.
Answer:
// here is code in c++ to find the approx value of "e".
#include <bits/stdc++.h>
using namespace std;
// function to find factorial of a number
double fact(int n){
double f =1.0;
// if n=0 then return 1
if(n==0)
return 1;
for(int a=1;a<=n;++a)
f = f *a;
// return the factorial of number
return f;
}
// driver function
int main()
{
// variable
int n;
double sum=0;
cout<<"enter n:";
// read the value of n
cin>>n;
// Calculate the sum of the series
for (int x = 0; x <= n; x++)
{
sum += 1.0/fact(x);
}
// print the approx value of "e"
cout<<"Approx Value of e is: "<<sum<<endl;
return 0;
}
Explanation:
Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".
Output:
enter n:12
Approx Value of e is: 2.71828
