Answer:
Range: [-2, 2] {y | -2 ≤ y ≤ 2}
Step-by-step explanation:
he given function is y = 2sinx
We have to find the range of the given function.
Since at y-axis sine function has the variance between -1 to 1 so range of y = sinx is [-1, 1]
and if the amplitude of sine function is 2 then sine function will vary from -2 to 2 which implies that range of y = 2 sinx will be [-2, 2]
So range of y = 2sinx is [-2, 2]
Read more on Brainly.com - brainly.com/question/4419238#readmore
Answer:
8x^6-10x^5+4x^4-5x^3-4x+5
Step-by-step explanation:
Lest distribute the expression given
this is multiply the first term (4x) with the longer expression (2x^5+x^3-1) and then, multiply the second term (-5) with the longer expression (2x^5+x^3-1).
When the above is finish, simply sum all together.
4x* (2x^5+x^3-1)= 8x^6 +4x^4-4x
-5*(2x^5+x^3-1)=-10x^5-5x^3+5
The sum of all together (respecting the coefficient they belong) is shown:
8x^6-10x^5+4x^4-5x^3-4x+5
//I'll use the discriminant rule for this.
b^2 - 4ac = 0 when one real root
Therefore, k^2 - 4*3*4= 0
k^2 = 48
k= +-4√3
That’s the answer for this problem
Answer:
identity
Step-by-step explanation:
