Question

Divide -3x^3-2x^2-x-2 by x-2

Answer 1

Let's do this by Briot-Ruffini

First: Find the monomial root

x - 2 = 0

x = 2

Second: Allign this root with all the other coeficients from equation

Equation = -3x³ - 2x² - x - 2

Coeficients = -3, -2, -1, -2

2 | -3 -2 -1 -2

Copy the first coeficient

2 | -3 -2 -1 -2

-3

Multiply him by the root and sum with the next coeficient

2.(-3) = -6

-6 + (-2) = -8

2 | -3 -2 -1 -2

-3 -8

Do the same

2.(-8) = -16

-16 + (-1) = -17

2 | -3 -2 -1 -2

-3 -8 -17

The same,

2.(-17) = -34

-34 + (-2) = -36

2 | -3 -2 -1 -2

-3 -8 -17 -36

Now you just need to put the "x" after all these numbers with one exponent less, see

2 | -3x³ - 2x² - 1x - 2

-3x² - 8x - 17 -36

You may be asking what exponent -36 should be, and I say:

None or the monomial. He's like the rest of this division, so you can say:

(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:

(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)

Just divide the rest by the monomial.