Question

Two rockets are lauched at the same time, but from different heights. The height y in feet of one rocket after t seconds is given by y = -16t² + 150t + 5. The height of the other rocket is given by y = -16t² + 160t. After how many second are the rockets at the same height?

Answer 1

Answer:

0.5 seconds

Step-by-step explanation:

Two rockets are launched at the same time, but from different heights.

$y = -16t^2+ 150t + 5$

$y = -16t^2 + 160t$

when the heights are same then y are equal. So equation both equations and solve for t

$-16t^2+ 150t + 5= -16t^2+ 160t$

Add -16t^2 on both sides

$+ 150t + 5=160t$

Subtract 150 t from both sides

$5=10t$

Divide 10 on both sides

t=0.5 seconds