$7y-2x+3 < 17\ \ \ \ |-3\\\\7y-2x < 14\ \ \ \ |+2x\\\\7y < 2x+14\ \ \ \ |:7\\\\y < \dfrac{2}{7}x+2\\\\y=\dfrac{2}{7}x+2\\\\for\ x=0\to y=\dfrac{2}{7}(0)+2=2\to(0,\ 2)\\\\for\ x=-7\to y=\dfrac{2}{7}(-7)+2=0\to(-7,\ 0)$

5 0

3 years ago

Solve the following simultaneous equations : with the help of steps 1. x + 2y = 1, 3x - y = 17

IRISSAK [1]

Answer:

x = 5, y = -2

Step-by-step explanation:

Given equations:

x + 2y = 1
3x - y = 17

From the first equation we get:

x = 1 -2y

Substitute x in the second equation, find y:

3x - y = 17
3*(1-2y) - y = 17
3 - 6y - y = 17
-7y = 17 - 3
-7y = 14
y = -14/7
y = -2

Find x:

x = 1 - 2y
x = 1 - 2*(-2)
x = 1 + 4
x = 5

6 0

3 years ago

What are the zeros of the polynomial function f(x) = x^3-10x^2+24x

Ludmilka [50]

Replace F(x) with y
y=x^3-10x^2+24x
To find the roots replace y with 0.
0=x^3-10x^2-24x
Rewrite the equation as
x^3-10x^2+24x=0
Factor the left side
x(x-6)(x-4)=0
The solution is a result of
x=0, x-6=0, and x-4=0

The answer is:
x=0, 6, 4

3 0

3 years ago