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iogann1982 [59]

4 years ago

13

Graph the polar equation r = 3 + 3 sin(theta)

1 answer:

Korolek [52]4 years ago

6 0

Find attached the graph and a table with some important points.

Note that every point of the graph is the extreme of a vector whose radius is r and angle is theta.

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What is the midpoint of the segment below? (2,3)(-3,-2)

soldi70 [24.7K]

Answer:

(-0.5, 0.5)

Step-by-step explanation:

If those two points are endpoints, just use the midpoint formula.

(-0.5, 0.5)

7 0

3 years ago

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I NEED HELP PLEASE! ;0

Fittoniya [83]

Answer:

4:6 or 2:3

Step-by-step explanation:

Since the ratio of mass of oxygen to carbon is 4:3, when there are two carbons the ratio will be 4:3*2=4:6=2:3. Hope this helps!

8 0

3 years ago

I saved $360 for one year.the bank paid me 20% interest.how much do i now have

Ann [662]

You have 360+360*20%=360+360*20/100=360+72
So you have 432

4 0

3 years ago

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Please help me with my math home work

Ket [755]

<u>page 1:</u>

$-\frac{8}{3} m = 6$

$-8m = 6(3)$

$-8m = 18$

$m = \frac{18}{-8}$

$m = -\frac{9}{4}$

$m = -2\frac{1}{4}$

<u>page 2</u>:

7)

$0.8x = 19$

$x = 19/0.8$

$x = 23.75$

8)

$0.12x = 1$

$x = 1/0.12$

$x =$ $\frac{25}{3}$

$x = 8\frac{1}{3}$

5)

3.3(x+4)

3.3x + 13.2

b.

$9-5\:\frac{1}{2}x-3\left(-2x+1\right)$

$9-\frac{11}{2}x-3\left(-2x+1\right)$

$6x-\frac{11}{2}x+9-3$

$x\frac{1}{2}+6$

$\frac{1}{2}x+6$

c.

$2.2(3.1+x)+3x$

$6.82+2.2x+3x$

$6.82+5.2x$

<u>page 3:</u>

1.

3/4 x = 60

x = (60*4)/3

x = 80

2.

2/5 x =42

x = (42*5)/2

x =105

3.

3/5 y = 40

y = (40*5)/3

y = $\frac{200}{3}$

y = $66\frac{2}{3}$

4.

$-\frac{8}{3}m =6$

$m = \frac{6*3}{-8}$

$m = -\frac{9}{4}$

$m = -2\frac{1}{4}$

5.

$\frac{5}{6} x =4$

$x = \frac{4*6}{5}$

$x =4.8$

6.

$\frac{5}{3} x =12$

$x = \frac{12*3}{5}$

$x =7.2$

4 0

3 years ago

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What is the equation of a line that is parallel to y=5/6x-10 and passes through (12,8)

Colt1911 [192]

The equation of a line that is parallel to y=5/6x-10 and passes through the point (12,8) is y=5/6-2.

y=5/6-2

5 0

4 years ago