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4 years ago

Students from the lowest income backgrounds are eligible for the _____.

SAT

2 answers:

Trava [24]4 years ago

6 0

Eligible for the FSEOG
Apex

Volgvan4 years ago

4 0

Cheaper college and a 401k

You might be interested in

A rectangular pyramid measures three feet by four feet at the base and has a height of seven feet. find its volume.

Slav-nsk [51]

The volume of the rectangular pyramid is 28 cubic feet.

<h3>How to find the volume of the pyramid?</h3>

The volume of a pyramid of base B and height H is given by:

$V = (1/3)*B*H$

Here we know that the height is H = 7ft, and the base is a rectangle of 4ft by 3ft, so the area of the base is:

$B = 4ft*3t = 12ft^2$

Then the volume of the pyramid is:

$V = (1/3)*7ft*12ft^2 = 28ft^3$

If you want to learn more about volumes:

brainly.com/question/1972490

#SPJ1

3 0

3 years ago

Examine the soil profile and use the drop-down menu to select what each label identifies. Label o label a label b label c.

uysha [10]

Answer:

Label O: Organic Material

Label A: Topsoil

Label B: Subsoil

Label C: Weathered rock

Explanation:

7 0

2 years ago

If you were studying for a test on ancient Egypt, which of these search engine results would probably be the least reliable sour

Darya [45]

The Best Option Would Be D Because British Museum-Egyptian Pyramids Would Be Helpful, But National Geographic:Egyptian Pyramids, Facts, Photos, And Diagrams Has That And More. C I Wouldn't Find Very Helpful, Because It's Just Focused On Pyramids, And B Is Totally Out Of The Picture. Hope That Helps!

6 0

3 years ago

Read 2 more answers

Evaluate the line integral, where c is the given curve. C (x/y) ds, c: x = t3, y = t4, 1 ≤ t ≤ 4.

skelet666 [1.2K]

We have

x = t³ ===> dx/dt = 3t²

y = t⁴ ===> dy/dt = 4t³

Then with the given parameteriztion, the line integral along C of x/y is

$\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^3}{t^4} \sqrt{(3t^2)^2 + (4t^3)^2} \, dt$

$\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac1t \sqrt{9t^4 + 16t^6} \, dt$

$\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{\sqrt{t^4}}t \sqrt{9 + 16t^2} \, dt$

$\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^2}t \sqrt{9 + 16t^2} \, dt$

$\displaystyle \int_C \frac xy \, ds = \int_1^4 t \sqrt{9 + 16t^2} \, dt$

$\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 32t \sqrt{9 + 16t^2} \, dt$

$\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 \sqrt{9 + 16t^2} \, d\left(9+16t^2\right)$

$\displaystyle \int_C \frac xy \, ds = \frac1{32} \cdot \frac23 \left(9+16t^2\right)^{\frac32}\bigg|_1^4$

$\displaystyle \int_C \frac xy \, ds = \frac1{48} \left(265^{\frac32} - 25^{\frac32}\right) = \boxed{\frac{265\sqrt{265}-125}{48}}$

6 0

3 years ago

Collge and career <br><br>the costs that show up on a college bill are called

qaws [65]

I’m 99.9% sure that’s called tuition

8 0

3 years ago