Calista should not give up on her education and she should set a timetable.
<h3>Advices that Calista can follow </h3>
- She should not give up, Calista should not give up on her education since she had already started, but continue to encourage herself.
- Set a timetable, Calista should have a timetable of how to run her day to day activities which can better help her have time for her studies.
Therefore, Calista should not give up on her education and she should set a timetable for herself that will work for her.
Learn more on importance of education here,
brainly.com/question/13341331
Answer:
See explanation
Explanation:
When an element tends to lose its valence electrons in chemical reactions, it behaves more like a metal.
When an element tends to gain valence electrons in chemical reactions, it behaves more like a nonmetal.
Metalloids have properties intermediate between those of pure metals and pure nonmetals. Usually, metalloids appear in groups where they are sandwiched between nonmetals and metals such as in groups 13, 14 and 15.
Based on the calculations, we have the following:
- The area of the sheet of paper is 96 square inches.
- The combined area of the triangle cutouts is equal to 36 square inches.
- The area of the parallelogram is equal to 60 square inches.
- The altitude of the parallelogram is equal to 6.51 square inches.
<u>Given the following data:</u>
- Dimension of paper = 12-inch by 8-inch.
<h3>How to calculate the paper's area.</h3>
Mathematically, the area of the paper is given by this formula:
![Area = length \times breadth\\\\Area = 12 \times 8](https://tex.z-dn.net/?f=Area%20%3D%20length%20%5Ctimes%20breadth%5C%5C%5C%5CArea%20%3D%2012%20%5Ctimes%208)
Area = 96 square inches.
<u>For the four (4) right triangles:</u>
- Dimension 1 = 2 inches by 9 inches.
- Dimension 2 = 3 inches by 6 inches.
Therefore, the combined area of the triangle cutouts is given by:
![A_2= (2 \times \frac{1}{2} \times 2 \times 9) + 2 \times \frac{1}{2} \times 3 \times 6\\\\A_2=18+18\\\\A_2=36\;in^2](https://tex.z-dn.net/?f=A_2%3D%20%282%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%202%20%5Ctimes%209%29%20%2B%202%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%203%20%5Ctimes%206%5C%5C%5C%5CA_2%3D18%2B18%5C%5C%5C%5CA_2%3D36%5C%3Bin%5E2)
<h3>The area of the parallelogram.</h3>
This would be determined by subtracting the area of the four (4) right triangles from the areas of the paper as follows:
![P = A_p -A_2\\\\P=96-36](https://tex.z-dn.net/?f=P%20%3D%20A_p%20-A_2%5C%5C%5C%5CP%3D96-36)
P = 60 square inches.
<h3>The altitude of the
parallelogram.</h3>
![P = base \times altitude\\\\Altitude =\frac{P}{base} \\\\Altitude =\frac{60}{9.22}](https://tex.z-dn.net/?f=P%20%3D%20base%20%5Ctimes%20altitude%5C%5C%5C%5CAltitude%20%3D%5Cfrac%7BP%7D%7Bbase%7D%20%5C%5C%5C%5CAltitude%20%3D%5Cfrac%7B60%7D%7B9.22%7D)
Altitude = 6.51 square inches.
Read more on parallelogram here: brainly.com/question/4459854
<u>Complete Question:</u>
A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimensions 2 inches by 9 inches, and the other two have the dimensions 3 inches by 6 inches. The resulting parallelogram has a base of approximately 9.22 inches.