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Nikitich [7]
3 years ago
5

If a and b are rational numbers and 5 +2 root 3/7+4 root3=a-b root 3;then a and b=

Mathematics
1 answer:
Usimov [2.4K]3 years ago
6 0

Answer:

           \bold{a=5\,,\quad b=-4\frac27}

Step-by-step explanation:

5+\frac{2\sqrt3}7+4\sqrt3=5+\frac27\sqrt3+4\sqrt3=5+4\frac27\sqrt3=5-(-4\frac27)\sqrt3

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romanna [79]

<u>(Note: this answer is assuming that the equation has to be put in slope-intercept format.)</u>

Answer:

y = \frac{1}{2} x - \frac{5}{2}

Step-by-step explanation:

1) Let's use the point-slope formula to determine what the answer would be. To do that though, we would need two things: the slope and a point that the equation would cross through. We already have the point it would cross through, (-3,-4), based on the given information. So, in the next step, let's find the slope.

2) We know that the slope has to be parallel to the given line, y = \frac{1}{2}x - 8. Remember that slopes that are parallel have the same slope - so, let's simply take the slope from the given equation. Since it's already in slope-intercept form, we know that the slope then must be \frac{1}{2}.

3) Finally, let's put the slope we found and the x and y values from (-3, -4) into the point-slope formula and solve:

(y- (-4))  = \frac{1}{2} (x - (-3))\\y + 4 = \frac{1}{2} (x + 3))\\y + 4 = \frac{1}{2}x+ \frac{3}{2} \\y = \frac{1}{2}x + \frac{3}{2} - 4\\y =  \frac{1}{2}x + \frac{3}{2} - \frac{8}{2} \\y = \frac{1}{2}x - \frac{5}{2}

Therefore, y = \frac{1}{2}x - \frac{5}{2} is our answer. If you have any questions, please do not hesitate to ask!

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