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satela [25.4K]
3 years ago
15

1/2x+4 in factored form

Mathematics
1 answer:
hammer [34]3 years ago
5 0
\frac{1}{2}x+4 =\boxed{\bf{ \frac{1}{2}(x+8)}}
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Hey! im confused on this. ill give more points if you end up being correct :)
Svetlanka [38]

Answer:

A

Step-by-step explanation:

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3 years ago
PLZ HELP ME OUT How do I know a number is rational or irrational?
Harrizon [31]

Answer: If a number is rational, it can be represented as a simple fraction, it can be written as a terminating decimal, and a repeating decimal.

If a number is irrational, it cannot be represented as a simple fraction, it cannot be written as a terminating decimal, and not as a repeating decimal. It never ends, never repeats, just like the constant pi.

Step-by-step explanation:

So if a number is rational, it can be represented as a simple fraction, it can be written as a terminating decimal, and a repeating decimal.

If a number is irrational, it cannot be represented as a simple fraction, it cannot be written as a terminating decimal, and not as a repeating decimal. It never ends, never repeats, just like the constant pi.

8 0
3 years ago
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alex41 [277]

Answer:

raise a product to a power.

you first simplify the parenthesis in the numerator by raising 2 by the power of three and multiplying the exponents.

i suck at explaining, but after the first step the expression looks like:

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Step-by-step explanation:

5 0
3 years ago
How many different triangles can you make with the following conditions: angles measuring 45 degrees and 90 degrees and an INCLU
kotykmax [81]

Answer:

One

Step-by-step explanation:

Clearly, one triangle can be constructed as the angles 45 and 90 do not exceed 180 degrees. (so "None" is not correct)

To show that only one such triangle exists, you can apply the Angle-Side-Angle theorem for congruence.

Since one triangle can be constructed, it remains to be shown that no additional triangle that is not congruent to the first one can be created: I will use proof by contradiction. Let a triangle ABC be constructed with two angles 45 and 90 degree and one included side of length 1 inch. Suppose, I now construct a second triangle that is different from the first one but still has the same two angles and included side. By applying the ASA theorem which states that two triangles with same two angles and one side included are congruent, I must conclude that my triangle is congruent to the first one. This is a contradiction, hence my original claim could not have been true. Therefore, there is no way to construct any additional triangle that would not be congruent with the first one, and only one such triangle exists.

3 0
3 years ago
Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?
Flura [38]

Answer:

The value to the given expression is 8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3

To find the value of the given expression:

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}

( By using the property ((\frac{a}{b})^m=\frac{a^m}{b^m} )

=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}

( By using the property (ab)^m=a^mb^m )

=\frac{(10^{12})(5^6)}{(10^9)(5^9)}

( By using the property (a^m)^n=a^{mn} )

=(10^{12})(5^6)(10^{-9})(5^{-9})

( By using the property \frac{1}{a^m}=a^{-m} )

=(10^{12-9})(5^{6-9}) (By using the property a^m.b^n=a^{m+n} )

=(10^3)(5^{-3})

=\frac{10^3}{5^3} ( By using the property a^{-m}=\frac{1}{a^m} )

=\frac{1000}{125}

=8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Therefore the value to the given expression is 8

3 0
3 years ago
Read 2 more answers
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