The "explanation" for the problem has a typo in it. There are 11 possible ice cream/yogurt flavors to choose from, regardless of whether any are low-fat, so the total number of ways of choosing any 2 from the selection is

In particular we want to count the number of ways of picking 1 ice cream and 1 yogurt flavor from the low-fat variety. There are 6 total choices that are not low-fat of which we choose 0, 3 choices of low-fat ice cream of which we choose 1, and 2 choices of low-fat yogurt of which we also choose 1. In terms of the binomial coefficient, this is

So the probability of getting such a combination is

.
Answer:
hi
Step-by-step explanation:
Solve the following system:
{3 x - 5 y = 7 | (equation 1)
{10 y - 4 x = 16 | (equation 2)
Swap equation 1 with equation 2:
{-(4 x) + 10 y = 16 | (equation 1)
{3 x - 5 y = 7 | (equation 2)
Add 3/4 × (equation 1) to equation 2:
{-(4 x) + 10 y = 16 | (equation 1)
{0 x+(5 y)/2 = 19 | (equation 2)
Divide equation 1 by 2:
{-(2 x) + 5 y = 8 | (equation 1)
{0 x+(5 y)/2 = 19 | (equation 2)
Multiply equation 2 by 2:
{-(2 x) + 5 y = 8 | (equation 1)
{0 x+5 y = 38 | (equation 2)
Divide equation 2 by 5:
{-(2 x) + 5 y = 8 | (equation 1)
{0 x+y = 38/5 | (equation 2)
Subtract 5 × (equation 2) from equation 1:
{-(2 x)+0 y = -30 | (equation 1)
{0 x+y = 38/5 | (equation 2)
Divide equation 1 by -2:
{x+0 y = 15 | (equation 1)
{0 x+y = 38/5 | (equation 2)
Collect results:
Answer: {x = 15
{y = 38/5 or 7.6 decimal
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