Answer:
Therefore the answer is 20.
Step-by-step explanation:
We know that
class interval = range / number of classes
But here number of classes is not given , so we use the formula
class interval = range / ( 1+ 3.322 log N)
where , range =maximum - minimum = 220-100 = 120
N= number of observations = 50
class interval = 120 / ( 1+ 3.322 * log 50) = 18.06
Rounding up to a convinient number
Thus , class intervai = 20
Therefore the answer is 20.
The value of n in given proportion is 16
<u><em>Solution:</em></u>
We have to find the value of "n" in the proportion
<em><u>Given proportion is:</u></em>
<em><u></u></em><em><u></u></em>
We can solve the above proportion by cross-multiplying
Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction
Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction
Set the two products equal to each other
Solve for the variable
Thus the value of n in given proportion is 16
The solution of the given equation is (3,6). The correct option is B.(3,6)
<h3>Given equations,</h3>putting the value of y from equation (1) in equation (2) , we get
substitute the value of x=3 in equation (1) we get,
Hence, the solution of given equation is (3,6).
So, the correct option is B.
For more details about the system of equations, follow the link: