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3 years ago

Need help with dividing

Mathematics

2 answers:

alexgriva [62]3 years ago

6 0

3 10 4
9 6 9
6 11 11
12 5 7
8 7 11
the answers are going across

Eva8 [605]3 years ago

4 0

1) 15/5 = 3 .

2) 27/3= 9

3)48/8 = 6

4) 84/7= 12

5)32/4= 8

6) 90/9 =10

7) 30/5= 6

8) 22/2 = 11

9) 60/12= 5

10) 21/3= 7

11) 44/11= 4

12) 54/6 = 9

13) 132/12 = 11

14) 70/ 10= 7

15) 99/9 = 11

HOPE THIS HELPS XD

ps. rate me brainliest

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Devon paid for 4 pounds of bananas with a $10 bill. He got back $4.00. What was the cost of 1 pound of bananas? $3.50 $24.00 $1.

Maksim231197 [3]

Answer:

24.00

Step-by-step explanation:

3 0

3 years ago

1. Popeye is lifting Olive Oyl off the ground by pulling her upward with a force of 108.1 N. She is pretty thin so she only weig

Debora [2.8K]

Answer:

1 m/s2

Step-by-step explanation:

Olive Oyl's weight = 10 × 9.81 = 98.1 N

This weight is a force acting downward because it is due to gravity.

Popeye pulls Olive Oyl up with a force of 108.1 N. Both forces act vertically but in opposite directions. Hence their resultant, R, is their difference and is in the direction of the larger force.

R = 108.1 N - 98.1 N = 10 N

This force causes an acceleration, a, on the mass, m, of Popeye.

R = ma

a = R/m = 10 N/10 kg = 1 m/s2

6 0

3 years ago

Read 2 more answers

Juan went out to eat dinner, and the meal cost $60.00. If Juan received an 18% discount, what was the total value of the discoun

DaniilM [7]

Answer:

The total value of the discount was $10.80.

Step-by-step explanation:

Since we are finding the value of the discount, we just need to find 18% of 60.

We can convert 18% into a decimal.

18%=0.18

Multiply.

0.18*60=10.8

The total value of the discount was $10.80.

6 0

3 years ago

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

Let $\bar X$ = sample average time spent studying

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

So, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0

3 years ago

Congress regulates corporate fuel economy and sets an annual gas mileage for cars. A company with a large fleet of cars hopes to

3241004551 [841]

Answer:

There is sufficient evidence that fuel economy goal has been attained.

Step-by-step explanation:

The hypothesis :

H0 : μ < 30.2

H1 : μ ≥ 30.2

The test statistic :

(xbar - μ) ÷ (s/√(n))

xbar = 32.12 ; s = 4.83 ; n = 50

Test statistic :

(32.12 - 30.2) ÷ (4.83/√(50))

1.92 ÷ 0.6830651

T = 2.811

Using the Pvalue from test statistic calculator :

Since we used the sample standard deviation, we use the T distribution

df = n - 1 = 50 - 1 = 49

Pvalue(2.811, 49) ; one tailed = 0.00354

At α = 0.05

Pvalue < α ; then we reject the null and conclude that there is sufficient evidence that fuel economy goal has been attained

4 0

3 years ago