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frutty [35]
3 years ago
8

Please help...................

Mathematics
2 answers:
kow [346]3 years ago
7 0
The answer is MPN! the angles should be equal that way
miss Akunina [59]3 years ago
6 0
ABC is equal to MNP. This is because you have to look at the order of the angles/sides. ABC goes from A with 3 congruency arcs to B with 1 congruency arc. For MNP, start with M that has 3 congruency arcs then go to the next angle with one congruency arc which is N
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Find the measurement of the indicated angle to the nearest degree
MaRussiya [10]

Answer:

42

Step-by-step explanation:

This time, you'll be doing SOH.

sin (x) = 39/59=0.66

then do sin^-1 (0.66)

x = 42 degrees (think this is correct I hope)

4 0
3 years ago
Jim works mowing lawns and babysitting. He earns $8.80 an hour for mowing and $8.10 an hour for babysitting. How much will he ea
kicyunya [14]

Answer: $8.80 for one hour of mowing and $40.50 for 5 hours of babysitting

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Jen Butler has been pricing​ Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 132.
laiz [17]
Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20

or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
8 0
3 years ago
(Multiple choice)
spayn [35]
I believe the answer is A
5 0
2 years ago
Given: \overline{AC} \perp \overline{BD} AC ⊥ BD and \overline{BD} BD bisects \overline{AC}. AC . Prove: \triangle ABD \cong \tr
Fofino [41]

Answer:

The Proof for

△ABD ≅ △CBD is below

Step-by-step explanation:

Given:

\overline{AC} \perp \overline{BD}

\overline{BD} \ bisects\  \overline{AC}

AD = CD      .........BD bisect AC

To Prove:

△ABD ≅ △CBD

Proof:

In  ΔABD  and ΔCBD  

BD ≅ BD              ....……….{Reflexive Property}

∠ADB ≅ ∠CDB    …………..{Measure of each angle is 90°( \overline{AC} \perp \overline{BD} )}

AD ≅ CD              ....……….{ \overline{BD} \ bisects\  \overline{AC} }

ΔABD  ≅ ΔCBD   .......….{By Side-Angle-Side Congruence test}  ...Proved

4 0
3 years ago
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