The range is how much it spans in f(x), f(x) is a line, it has no max/min, so it's enough to substitute the least and greatest values of your domain:
f(-2) = -5, f(4)=7,
Range = [-5,7]
Well, a distance-preserving transformation is called a rigid motion, and the name suggests that it <em>moves the points of the plane around in a rigid fashion.</em>
A transformation is distance-preserving if the distance between the images of any two points and the distance between the two original points are equal.
If that's confusing, I get it; basically if you transform something, the points from the transformation are image points. Take the distance from a pair of image points, and take the distance from a pair of original points, and they should be the same for a <em>rigid </em>motion.
I keep emphasizing this b/c not all transformations preserve distance; a dilation can grow or shrink things. But if you didn't go over dilations, don't say nothin XD
Answer:
198.6 with the remaining 6
Step-by-step explanation:
596/3
596/3 = 198.666666667 as a decimal form
596/3 = 198.67 in 2 decimal places
596/3 = 198.7 to the nearest tenth
596/3 = 198.67 to the nearest hundredth
596/3 = 198.667 to the nearest thousandth